min_val = a[1]
    count = 0  
    for elem in a
        count += 1
        if elem < min_val
            min_val = elem
        end
    end
    return min_val, count
end

# 调用函数
a = [8 5 6 9 4 5 6 1 5 -1]  
min_val, count = find_min(a)
println("最小元素: ", min_val)
println("循环次数: ", count)